Java- Builiding a recursion that replace even digits with zero -

hello need build recursion replace digits zero: exmaple - number 1254 1050 number 332- 330 , number 24 - 0

i started working on got pretty clueless after while

 public static int replaceevendigitswithzero(int number){     if(number<1)         return number;     if(number%2==0 && number%10!=0){         int temp=number%10;         return(number/10+replaceevendigitswithzero(number-temp));     }     return(replaceevendigitswithzero(number/10)); } public static void main(string[] args) {         int num1 = 1254;         system.out.println(num1 + " --> " + replaceevendigitswithzero(num1));          int num2 = 332;         system.out.println(num2 + " --> " + replaceevendigitswithzero(num2));          int num3 = 24;         system.out.println(num3 + " --> " + replaceevendigitswithzero(num3));          int num4 = 13;         system.out.println(num4 + " --> " + replaceevendigitswithzero(num4));     }  } 

since method looks @ last digit, should call input / 10 when input >= 10.

you take value returned recursion, multiply 10 , add last digit back, if odd.

public static int replaceevendigitswithzero(int number) {     int result = 0;     if (number >= 10)         result = replaceevendigitswithzero(number / 10) * 10;     if (number % 2 != 0)         result += number % 10;     return result; }