dart - What is the smartest way to find the larger / smaller of two numbers -

in search of smartest, efficient , readable way below:

int 1 = 1, 2 = 2; int larger = 1 < two?two:one; 

i prefer(or variadic version of below):

int largest(one,two){return one<two?two:one;} int larger = largest(one,two); 

but dart has no inline or macro.

with list:

var nums = [51,4,6,8]; nums.sort(); in largest = nums.last 

or(thank you, günter zöchbauer):

print([1,2,8,6].reduce(max)); 

using math library:

import 'dart:math'; int largest = max(21,56); 

probably best, how efficient max in comparison first approach?

why question?
first approach must check comparisons done right each of them;hundreds of them sometimes. second, 1 function verify, hundreds of function calls.

i'm pretty sure just

import 'dart:math'; int largest = max(21,56); 

is best way. small enough inlined compiler (dart2js, vm) , least surprise reader. custom implementation reader had investigate function sure does.

for collections of values find elegant way

from https://stackoverflow.com/a/20490970/217408

import 'dart:math';  main(){   print([1,2,8,6].reduce(max)); // 8   print([1,2,8,6].reduce(min)); // 1 } 

reordering list min/max quite inefficient

var nums = [51,4,6,8]; nums.sort(); in largest = nums.last