XSLT to remove duplicates completely -

i know there solutions plenty remove duplicates, 1 different. need remove element output if duplicate. input:

<sanctionlist>     <row>         <personid>1000628</personid>         <personid>1000634</personid>         <personid>1113918</personid>         <personid>1133507</personid>         <personid>1113918</personid>     </row> </sanctionlist> 

output expected:

<sanctionlist>     <row>         <personid>1000628</personid>         <personid>1000634</personid>         <personid>1133507</personid>     </row> </sanctionlist> 

here tried parser returns 1 each of groups. shouldnt return 2 personid 1113918 since appears twice in list?

<?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/xsl/transform"  xmlns:xs="http://www.w3.org/2001/xmlschema"    version="2.0">     <xsl:strip-space elements="*"/>      <xsl:template match="node()|@*">         <xsl:copy>         <xsl:apply-templates select="node()|@*"/>         </xsl:copy>         </xsl:template>      <xsl:template match="sanctionlist">         <xsl:for-each-group select="row" group-by="personid">             <xsl:text> count </xsl:text>             <xsl:value-of select="current-grouping-key()" />                 <xsl:text> </xsl:text>             <xsl:value-of select="count(current-group())" />         </xsl:for-each-group>     </xsl:template>  </xsl:stylesheet> 

thanks kindly!

i know there solutions plenty remove duplicates, 1 different. need remove element output if duplicate

use short , simple transformation (both in xslt 2.0 , xslt 1.0):

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/xsl/transform">  <xsl:output omit-xml-declaration="yes" indent="yes"/>  <xsl:strip-space elements="*"/>  <xsl:key name="kpersonbyval" match="personid" use="."/>    <xsl:template match="node()|@*">     <xsl:copy>       <xsl:apply-templates select="node()|@*"/>     </xsl:copy>   </xsl:template>    <xsl:template match="personid[key('kpersonbyval', .)[2]]"/> </xsl:stylesheet> 

when transformation applied on provided xml document:

<sanctionlist>     <row>         <personid>1000628</personid>         <personid>1000634</personid>         <personid>1113918</personid>         <personid>1133507</personid>         <personid>1113918</personid>     </row> </sanctionlist> 

the wanted, correct result produced:

<sanctionlist>    <row>       <personid>1000628</personid>       <personid>1000634</personid>       <personid>1133507</personid>    </row> </sanctionlist> 

explanation:

1. a wellknown design pattern copying existing xml document , deleting/replacing/inserting nodes copy, overriding identity rule.
2. in particular case task delete <personid> elements. done providing matching template no (empty) body.
3. the criterion deletion element must have duplicate -- is, @ least 2 <personid> elements must exist, having same string value. conveniently done using <xsl:key> declaration , key() function elements same string value.
4. finally, in match pattern of empty (deleting) template check if node-set of equally-valued elements has second element.

note: can learn more <xsl:key> declaration , key() function in module 9 of pluralsight training course "xslt 2.0 , 1.0 foundations"