python - Scrapy LinkExtractor cannot extract links with href of mailto: -

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i'm using linkextractor class extract links page

for link in linkextractor(allow=()).extract_links(response):     print link.url

this prints urls page. can't seem links have href equal mailto: link. example:

<a href="mailto:example@gmail.com">mail</a>

do need pass argument linkextractor make grab links mailto: ?

you don't need use linkextractor urls need, use xpath response object.

all_links = response.xpath('//a/@href').extract()

linkextractor focuses on getting links follow, that's why avoids mailto links default.


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