java - Xlsx issue, cell.getCellStyle().getDataFormat() changing value after adding or removing date -

-

i using block of code cell.getcellstyle().getdataformat() . changes it's values after adding or removing content xlsx. should done in case?

enter image description here

first cell 21/01/2016 returns cell.getcellstyle().getdataformat() retuns 14 when add rows cell.getcellstyle().getdataformat() returns 165 

if (dateutil.iscelldateformatted(cell)) {     double val = cell.getnumericcellvalue();     date date = dateutil.getjavadate(val);      string datefmt = null;     system.out.println(cell.getcellstyle().getdataformat());     xssfcellstyle style = (xssfcellstyle) cell.getcellstyle();     system.out.println("in int: "+style.getdataformat());      if (cell.getcellstyle().getdataformat() == 14) {          system.out.println("14");         datefmt = "dd/mm/yyyy";      } else if(cell.getcellstyle().getdataformat() == 165) {          system.out.println("165");         datefmt = "m/d/yy";     } else if(cell.getcellstyle().getdataformat() == 166) {         system.out.println("166");         datefmt = "d-mmm-yy";      } else if(cell.getcellstyle().getdataformat() == 167) {          system.out.println("167");         datefmt = "mmmm d yyyy ";     } else if(cell.getcellstyle().getdataformat() == 168) {          system.out.println("168");         datefmt = "m/d/yyyy";     } else if(cell.getcellstyle().getdataformat() == 169) {          system.out.println("169");         datefmt = "d-mmm-yyyy";     } else {         datefmt = cell.getcellstyle().getdataformatstring();     }      system.out.println("datefmt "+datefmt);     value = new celldateformatter(datefmt).format(date);     system.out.println("date "+value); }

i posting answer in case needs in future. 

          if (dateutil.iscelldateformatted(cell)) {                 double val = cell.getnumericcellvalue();                 date date = hssfdateutil.getjavadate(val);                 string datefmt = null;                  if(cell.getcellstyle().getdataformat()==14){                     datefmt = "dd/mm/yyyy";                     value = new celldateformatter(datefmt).format(date);                 }                 else{                     dataformatter fmt = new dataformatter();                     string valueasinexcel = fmt.formatcellvalue(cell);                     value = valueasinexcel;                 }            }

Comments

Post a Comment

Popular posts from this blog

SVG stroke-linecap doesn't work for circles in Firefox? -

-
i've got problem svg stroke-linecap attribute. i've got circular progress bar in angularjs , set outer circle (blue one) have rounded "ends". @ fiddle . <svg ... height="130" width="130"> <!-- ngif: background --> <circle ... ng-if="background" fill="#fff" class="ng-scope" stroke-width="13" stroke="#cc3399" r="57.5" cy="65" cx="65" stroke-linecap="round" /> <!-- end ngif: background --> <circle ... fill="none" stroke-dashoffset="36.12831551628261" stroke-dasharray="361.28315516282623" stroke-width="13" stroke="#432db3" stroke-linecap="round" r="57.5" cy="65" cx="65" transform="rotate(-89.9, 65, 65)" /> </svg> how can that? ...
Read more

routes - Laravel 4 Wildcard Routing to Different Controllers -

-
realizing i'm going take beating this, have several questions "best practices" when constructing laravel route. do laravel routes run "first come first serve" top bottom? if route found, pass control controller (or perform action) , terminate? i have part of application acts url shortner. so, route looks this: route::get('/{id}', array('as' => 'home.text', 'uses' => 'homecontroller@text'), function($id){ //make sure id exists before pushing controller. if (storage::where('shortcode','=', $id)->count() > 0) { // route found } }); how can improved? one, i'm not sure how pass processing on controller conditionally.. sort of controller::make() ..? 3) there better way in laravel check if record exists versus doing mode::where('column','=','value')->count() 4) have legacy urls http://url.com/?...
Read more

cross browser - XSLT namespace-alias Not Working in Firefox or Chrome -

-
i transforming xhtml xhtml, need xslt stylesheet part of resulting document (the stylesheet contained in <script type"text/template"> element. using the xsl:namespace-alias instruction, works fine in ie, fails in both chrome , firefox. here relevant code: <xsl:output doctype-system="about:legacy-compat" omit-xml-declaration="yes" indent="yes" method="html" media-type="application/xhml" encoding="utf-8"/> <xsl:namespace-alias stylesheet-prefix="wxsl" result-prefix="xsl" /> <xsl:template match="head"> <!-- code omitted clarity --> <script type="text/template"> <wxsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/xsl/transform" xmlns="http://www.w3.org/1999/xhtml" xmlns:xhtml="http://www.w3.org/1999/xhtml" xmlns:eli="local"> ...
Read more